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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2007 18:15:04 IST
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A certain charge Q is divided into 2 parts q and(Q-q). how should the charges Q & q be related,so that when q & (Q-q) placed at a certain distance apart experience max electrostatic repulsion?
Two identical charged spheres are suspended by strings of equal lengths make an angle of 30 degrees with each other.when suspended in a liquid of density 0.8g/cc ,the angle remains same.what is the dielectric constant of the liquid?(density of the material of the sphere is 1.6g/cc)
A conductor A has a cavity in which another conductor having chrge q is put keeping it away from the walls of A.what will be the charge on the surface of A?
could anyone tell me where these q's are from?
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28 May 2007 18:21:38 IST
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help anyone!
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28 May 2007 18:24:41 IST
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for first 1:2
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28 May 2007 18:32:32 IST
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the answer for first is Q/2
firstly write an general expression of their force and differentiate it and put it equal to zero.
please rate
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yugank
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for second question refer to G.C Agrawal of batla and sons
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yugank
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28 May 2007 19:43:18 IST
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the others??
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28 May 2007 19:50:20 IST
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ans of Q1
for max electric force df/dq = 0
where f = q(Q-q) = qQ - q^2
df/dq = Q - 2q=0
= q = Q/2
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28 May 2007 19:52:40 IST
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thanks.2nd and 3rd?
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28 May 2007 20:36:35 IST
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help(!!!)
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28 May 2007 22:24:07 IST
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first question appeared in DCE exam held on 27 may 2007 that is this sunday
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28 May 2007 23:11:16 IST
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dielectric const is given by
k = p/p-q
where p is the density of the material ans q is density of liquid
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What i wud lyk to be is unique....Govind |
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30 May 2007 18:47:26 IST
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Ans1> F is directly proportional to (q1q2) Therefore for max repulsive force q1 = q2 = Q/2 Ans3> -q at the inner surface & +q at the outer surface of other cavity. Do rate for me!!
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<TR><TD>
     
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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30 May 2007 20:02:25 IST
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ans 3: I think the charge on the surface of conductor is 0
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30 May 2007 20:04:17 IST
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as everone hav said ans 4 first one is Q/2.
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30 May 2007 20:11:09 IST
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