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Electricity

Blazing goIITian

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23 Mar 2008 09:16:58 IST

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495

electrostatics

None

inside a pherical charged regoin, with uniform charge density

there is a spherical cavity having centre at O' as shown in figure

(a) at point O,electric field is greater than that of the point O'

(b)O' is at higher potential that that of point p

(c)O' is at a higher potential that that of point r

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Comments (9)

kewlslayer

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23 Mar 2008 09:26:07 IST

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point O is on the surface of the cavity and not inside the cavity

rest alll the points are inside the cavity

kewlslayer

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23 Mar 2008 15:42:46 IST

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koi to solve kar do!!!!!!!!!!!!

dheer Bhatia

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23 Mar 2008 16:03:39 IST

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i think a is corrct option !!!

just use fact

e inside = pr/3epcilonnot = 3kqr/R^3

e surface = kq/r^2

n always e surface is max.

plz rate if useful

cheers

Ananth Patri

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23 Mar 2008 16:21:21 IST

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i think ans is a ???

kewlslayer

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23 Mar 2008 17:03:17 IST

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the answer given in the book is b and the reason given is field is uniform and directed along OO'

but i think it should be (a) because field at O' will be 0 and at O would be non zero.but the book says b

Rahul Udiaver

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23 Mar 2008 17:26:06 IST

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Hey all,

I think the ans shud b (a) due 2 radial symmetry of E in a spherical conductor, but the ans is given (b), but always trust yr concepts more than the book!!!

kewlslayer

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23 Mar 2008 17:28:32 IST

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lets c wat others have to say but i think it shud be a

Abhijith

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24 Mar 2008 06:22:26 IST

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Option "B" is definitely not right. Inside a cavity, the electrical field is 0 due to electrostatic sheid.

Hence O' , 'p' and 'r' are at the same potential. So option 'b' and 'c' are wrong which leaves us only with option 'a'.

The_Emperor

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24 Mar 2008 09:01:21 IST

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*****Edited

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