IIT JEE , AIEEE Forum - Physics , Electricity

saad_amu

two point charges Q1=+1micro coulomb and Q2=-2micro coulomb are placed at A and B the distance between the charges is 4cm. Aline of force emanates from Q1 making an angle 90 degrees with AB find at what angle the line of force leaves Q2??

hsb

this line will meet surface of q2 normally. now lines of force terminate at -ve charge
so the line will not leave q2. do correct me if i am wrong

ketan007

THERE IS NO NEED TO TRY SUCH QUESTIONS

tarun_bits

the line of force will not leave Q2 at all....but enter in it..means end there ( by convention)

sparshagrwal

lines will come in as in negative charge it always come towards charge....................

saad_amu

I HAVE ALSO APPLIED THE SAME LOGIC BUT THE ANSWER GIVEN IS 60 DEGREES. IT IS A QUESTION OF A STUDY PACKAGE OF NARAYANA

sagarvaze

simple
if a is angle line comes out from q1 and b is angle line goes into q2 then
q1/q2 = sin^2(b/2)/sin^2(a/2)

so 1/2= sin^2(b/2)/sin^2(pi/4)
sin^2(b/2)=1/4
b/2=30
b=60

and line does not leave but goes into q2 it must be a misprint.
rate me

saad_amu

WHAT FORMULA ARE YOU USING?? FROM WHERE DO YOU GET THE FORMULA ?? AND IN WHICH CASES IT CAN BE APPLIED? PLEEEEASE

sagarvaze

In HC Verma Electric Field and Potential short answer question there is a question of two charges q1 and q2 and field lines drawn. We have to find the relation between the two angles.
You have to assume that number of lines entering q2= number of lines coming out from q1 * (q2/q1)
Then you can prove it using gauss law and using solid angles
rate me

krishna.gopal

Line of force can not come out from a negative charge

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