IIT JEE , AIEEE Forum - Physics , Electricity

ashgirl

You charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected

to the plates from touching each other. When you pull the plates apart, do the following

quantities increase, decrease, or stay the same? (a) C; (b) Q ; (c) E between the

plates; (d)

V ; (e) energy stored in the capacitor.

also answer the questions for the situation in which the battery remains connected to the capacitor while you pull the plates apart.

plz give reason too!!!

rhd92781

C decreases coz it depends on the dimensions of the capacitor = Ae/d
Q remains same
E=(sigma)e remains same
V increases coz V=-Ed (d increases). also by q=CV (C decreases so V increases)

2) C decreases (same)
V remains same coz its maintained by the battery.
Q=CV, therefore it decreases
E decreases coz d increases (E=-V/d)

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