Find Charge on each capacitor, the potential difference between plates of each capacitor and the potential difference of the circuit in the foll diagram. 

(Diagram on next post)

Also explain how, please. 

I actually know but i am scared of attempting it..

I dont wanna give u a wrong answer

Try. If its wrong, someone will correct you. 

the circuit is equivalent to one havin a battery of 9V connected 22 capacitors of 2uF in series



so q=CV=1*9=9uC on each capacitor



pd across each wod be 4.5V

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alternatively u can use kirchoffs rule



assumptn :charges on top plate lft cap=q1 on rt -q2



then q1-q2=0 (batry is neutral device so plates can b treated as isolated)



-q1/2+3-q2/2+6=0



solving ull get the same ans!!!!!!!!