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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 19:39:51 IST
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find current in 5 ohm resistor.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 19:41:27 IST
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diagram is not visible...
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I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 19:47:11 IST
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just click on the figure
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 19:55:12 IST
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heyy simple one yaar just apply Kirchoff's law
suppose the 5 volt battery draw i current
then 5 - 5i - 10 = 0
therefore i = 1 amp. - ans..
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I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 19:58:32 IST
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SIMPLE CURRENT=3
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 20:49:53 IST
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Yes, current here = 3A. Use Superposition theorem.
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2008 20:55:52 IST
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@ akshay
you have wrongly applied the kirchoff's law.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 07:49:43 IST
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I ALSO USED SUPERSOTION METHOD VERY USEFUL
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 08:20:53 IST
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WILL U PLEASE TELL ME WHAT IS THIS SUPERPOSITION THEORAM?????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 08:40:19 IST
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Using Nodal Analysis ->
Potential difference across 5ohm resistor = 10 - (-5) = 15 V
Hence, 15 = i * 5 or i = 3A
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Impossible To be Impossible is Impossible |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 09:48:37 IST
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wait i m posting visible diagram.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 09:57:24 IST
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sorry for that diag. here visible diagram is posted.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 09:58:10 IST
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so sorry. resistor is of 5 ohm as indicated in dag.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 10:06:27 IST
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Superposition theorem is very simple. Basically you consider each of the voltage sources independently, removing the other source, and find the contribution of these sources across a circuit element, and then add the net result.
Example, in this problem: consider the 5 V battery first. It delivers a current of 1 A across the resistor. Now consider the 10 V battery. It delivers a current of 2 A across the resistor. So, the total current due to both the sources = 1+2 A = 3A. (Note that directions are important)
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2008 10:10:49 IST
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karthik u r missing something. in superposition theorem, when one voltage source is taken in action all other voltage sources r |