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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jun 2007 22:21:48 IST
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A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the gauss law, find the flux of the electric field due to charge through the surface of hemisphere.
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sikha
Success is how high you bounce when you hit bottom. |
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11 Jun 2007 22:33:29 IST
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Hi success_seeker
Flux=Q/2
Consider a spherical surface with the charge placed at its centre.
the flux thr it=q(enclosed)/
by symmetry the flux thr the hemispherical surface is half of the spherical one
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12 Jun 2007 11:59:29 IST
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if symmetry arguments gauss law...then we will have to solve it by integration...that will become complex....
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12 Jun 2007 12:01:06 IST
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the electric field lines of the charge pass through the hemisphere normal to its surface...
divide the hemisphere into thin rings...and then try to solve it ...
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12 Jun 2007 12:04:30 IST
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q/2e
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CSE AT NIT JALANDHAR
OM BHURBHAVA SWAHA TATSVITTURVARENIUM BHARGODEVESYA DHIMAHI DHIYO YOHNA PRACHODAYAT |
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12 Jun 2007 12:09:29 IST
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the answer of course is q/2ep.
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12 Jun 2007 12:11:40 IST
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i think it should be q/2episolon naught
(permittivity of free space)
and because for the whole sphere it would be q/e only
so therefore that ur anwser
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WIthout going for symmetry arguments and integration, gauss's law is the convinient way of finding flux throught the hemi spherical surface.
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The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
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