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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jan 2008 19:57:49 IST
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1)In which position of second charge Q, flux of electric field through the hemisphere remains unchanged. a) A b)B c)C d)D
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jan 2008 21:21:42 IST
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one of the best questions on Gauss's Law given in H.C.Verma.. the answer is A and D ........i'll post the explanation if u want.............
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jan 2008 15:25:07 IST
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see friend......ne field line passing through B n the hemisphere may or maynot cross the hemisphere again,...so flux may b changed...same is the story wid C ...bt look at A and D ...ne field line passing through them will definitely cut the hemisphere twice...thus producing no change in the net flux....r u satisfied ...if yes then pleez rate me n if nt ..tell me i ll make it clearer..... god bless u
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jan 2008 17:33:16 IST
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i think i got it....
but harsha_27 , can you post the solution please
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jan 2008 22:57:19 IST
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see the electric flux through the hemisphere remains
same only if no charges are induced on the inner
surface of the hemisphere(by Gauss's Law)
and also we know that presence of hemisphere should
not indeed cannot alter the effect of electric field
produced by the charge Q ,means (observe
carefully) the direction and magnitude of electric
field produced by the charge Q in region 1 must not
alter due to the presence of hemisphere in b/w
........so in order that not to happen induced
charges are arranged on the h.s. in such a way that
they exactly continue the lines of force originally
produced by the charge Q .....got it? and rest the
diagram itself explains (see the figures
carefully).............only in figure 1 ,the
arrangement of induced charges effect the flux
through the h.s. .........in fig 2 they won't
......hence A and D are correct ..........got it
now???? want more .............i'm ready to explain
.......so don't hesitate .......hope that doesn't
require .......u've got it by now.........
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>.>>>
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jan 2008 12:38:12 IST
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i m very sorry to say bt harsha u r nt wholly correct......that is what i think
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jan 2008 13:11:10 IST
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ok........ tell me what u think mohit
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jan 2008 17:02:15 IST
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what if i make the charge distribution like this??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jan 2008 17:36:02 IST
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i'm not saying that the distribution must be exactly
as what i've drawn ......it may be sth like that but
the main idea is "presence of hemisphere should
not indeed cannot alter the effect of electric field
produced by the charge Q ,unless it is a
non-conducting one " the distribution may be sth like
below see i've drawn the net field lines also.......
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jan 2008 18:07:08 IST
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u r confusing me friend
make it clear...
can i expect some experts view???
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