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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Gauss's Law- HCV2 Pg 141 Q11
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payal_bon (32)

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Gauss's Law- HCV2 Pg 141 Q11
    
payal_bon (32)

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A charge Q is distributed uniformly within the material of a hollow sphere of inner and outer radii r1 and r2. Find the electric field at apoint P a distane x away from the centre for r1
Ans: Q9x^3-r1^3)/4piEox^2(r2^3-r1^3)
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ganesha1991 (1700)

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see
@ = Q / 4/3 pie [r2^3 - r1^3]

now
E = Q/R^2 4pie Eo
but Q = @ * 4/3pie [ x^3-r1^3]
= Q / 4/3 pie [r2^3 - r1^3] * 4/3pie [ x^3-r1^3]
and R=x
so
E =( Q / { 4/3 *pie [r2^3 - r1^3]} * 4/3*pie [ x^3-r1^3] ) / 4Eo pie x^2
= Q(x^3-r1^3)/4piEox^2(r2^3-r1^3)
cancelling 4/3 pie
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