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Electricity
18 Mar 2008 22:28:43 IST
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18 Mar 2008 22:35:04 IST
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let
Q1 = initial charge on 5uF capacitor = 120 uC
Q2= initial charge on 6 uF capacitor = 72 uC
on being connected as given, let charges on both capacitors redistribute such that
q1 = final charge on 5uF capacitor
q2 = final charge on 6uF capacitor
required eqns. are
q1 + q2 = (120-72) = 48 (this en. comes from conservation of charge)
secondly
in stable state, potential across both capacitors are equal
then q1/5 = q2/6
substituting the value of q2 in first eqn.,
q1 = 48 x 5/ 11 = 21.8
and q2 = 26.2
this completes the ans
Q1 = initial charge on 5uF capacitor = 120 uC
Q2= initial charge on 6 uF capacitor = 72 uC
on being connected as given, let charges on both capacitors redistribute such that
q1 = final charge on 5uF capacitor
q2 = final charge on 6uF capacitor
required eqns. are
q1 + q2 = (120-72) = 48 (this en. comes from conservation of charge)
secondly
in stable state, potential across both capacitors are equal
then q1/5 = q2/6
substituting the value of q2 in first eqn.,
q1 = 48 x 5/ 11 = 21.8
and q2 = 26.2
this completes the ans
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just use the concept that the two connected plates are mauntained at same potential after stedy state
if u hav doubt, i will post the solution
DO RATE ME