H.C>Verma part 2 age no.167 . question no.25 0r 27.Please answer any one

I can not post the question as figure is involved in it

well i will try out the 27th one

look firstly 2F and 2F are in series = C_eq=1F

Now it is in parallel to 1F=C_eq=2F which is inturn in series with 2F capacitor=1F

now it is again in paralell with 1F=2F

finally it is in series with 2F

Therefore C_eq=1F                      ............................Ans

Plz correct me if i am wrong

Rate if correct

hey in 25 u want which part

i am solving the 1 part



the net capacitence is = 12/11



hence charge thrugh battery = 144/11



now in the charge that will go in second loop (which contain the

two capacitor of 2 and 4) will be 48/11



hence V = 48/11 / 4 ( V = Q/C)

V= 12/11