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Electricity

Cool goIITian

Joined:	4 Dec 2008
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7 Apr 2010 16:54:45 IST

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if we hv a solid conducting sphere( rad=r) hving chrge Q nd a pt P lies inside it at a dist R

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if we hv a solid conducting sphere( rad=r) hving chrge Q nd a pt P lies inside it at a dist Rr frm d cntre in the same strght line as P dn elec field at P due to induced chrges=( shudnt d ans be 0 as P lies inside a conductin body?)

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siDDhESwaR MuKhErjEE

Blazing goIITian

Joined: 15 Nov 2009

Posts: 608

7 Apr 2010 17:14:00 IST

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nice question pragya...but don't think it will be zero.

pragya

Cool goIITian

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7 Apr 2010 17:25:12 IST

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why??? whtevr chrges r induced shud lie outside on d surface of sphere dn elec field shud b 0??

Arjun Virmani

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Joined: 1 Jun 2009

Posts: 1294

7 Apr 2010 18:26:36 IST

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According to Gauss law..

The electric flux through any closed surface is proportional to the enclosed electric charge.

Flux is total field thru an area..

It doesnot depend on the distribution of the charges outside or inside but only how much charge is present inside....

thrfr..

their will be a field at P if their is charge present in the solid sphere below P....if their is charge outside P (even if it is on the surface or anywhere outside P) there will b no electric field at P......below P implies to that the charge is in an imaginary spher which passes thru P.....imaginary spher is Gaussian Surface here....)..

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