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FORUM.EXPERT (0)

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Two fixed equal positive charges, each of magnitude  5x10-5C are located at points A and B, separated by a distance of 6 m. An equal and opposite charge moves towards them along the line COD, the perpendicular bisector of the line AB. The moving charge, when reaches the point C at a distance of 4 m from O, has a kinetic energy of 4 joules. Calculate the distance of the farthest point D which the negative charge will reach before returning towards C.

    
trueblue29 (16)

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11m from O or something like tht?
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Conjurer (615)

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I am getting 8.5m app.


Using the energy equation.


0 = Delta KE + Delta PE


0 = 4 + (2KQq/root(x^2 +36) - 2KQq/5)


 


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shamips (24)

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Answer should be sqroot of 72=8.5
since total energy at C and D will be same

-2qqk/5 + 4 = -2qqk/root(x^2 + 9) +o
PE KE PE KE
at c at d

put k=9x10^9 and q=5x10^-5
=> x^2=72

psshami
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trueblue29 (16)

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oh yeah..sorry made a mistake
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krishna.gopal (2399)

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Right answers. Well done.

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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