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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 May 2007 20:32:20 IST
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Suppose that you have been given N identical point charges and you have arranged them in a circular region of area A such that the potential energy of the system is minimum.Then the distance between two adjacent charges would be:-----------
i)  (A /  )
ii) (NA / )
iii) (3A / N )
iv) None of these
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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15 May 2007 21:49:45 IST
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The charges should be placed on the circumfrence of the cirle at equal distance from each other and the angle subtended by any two adjacent charges at the center is 2(pi) / N. Since you know the area, you can find the radius and then find the distance between two charges using cosine rule.
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15 May 2007 22:37:49 IST
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since the potential must be minimum , the entire no of charges must be spread out over the circular area , such that a uniform surface charge density of Nq/A is obtained
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24 May 2007 01:39:28 IST
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COME ON ........mORE ANSWERS PLEASE......
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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25 May 2007 11:35:14 IST
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I am sure C.V.Raman sir is right.
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27 May 2007 20:21:07 IST
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i think ramman sir has explained perfectly..if the n chargesare eqvidistantthe potential would be min
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sighning of
smriti |
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