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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Aug 2007 12:51:04 IST
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Find the electric field strength vector at the centre of a ball of radius R with volume charge density = ar , where a is a constant vector and r is a radius vector drawn from ball?s centre
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Aug 2007 15:36:56 IST
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divide the ball into infinite shells...charge at one shell... dq= (rho)4pir^2 dr put the value of rho=ar and integrate from 0 to R ...u will get toatal charge ...and hence u can find E.
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For rIn Neeraj's answer if u integrate from 0 to r (r = k*a*pi*r^2
FOR r >R Q inclosed = a*pi*R^4 and E =KQ/r^2
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Aug 2007 11:57:18 IST
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guys please check kriashna jee's answer. if any doubt, you can re-confirm the steps.
cheers!
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