two similar spheres having +q and -q charges are kept at a certain distance . F force act b/w da 2. if in da middle of 2 spheres , another similar sphere having +q is kept,then it experince a force in magnitude n direction as.............

 

I'm assuming the distance between the charges as 'r' and let them be placed at A and B

 

F_AB = q²/4₀ r²

 

now +q is placed btw the 2 charges at O

 

F_{due to +q} = 4q²/4₀ r² AB  = 4F_AB  AB - bold represents vector

 

F_{due to -q} = 4q²/4₀ r²  AB  = 4F_AB  AB opposite charges attract......

 

 

so the magnitude of the force experienced by the charge placed in between is

 

F _net = 8F_AB

 

so our answer is 8F towards -q charge

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cheers!!!

 

 

the most simple approach wud be

F  1/r²

 

so u get

4F and 4F due to the 2 charges along the same direction (ie) towards -q charge

cheers!