for first question apply gauss law
take an arbitrary surface symmetrically about the central line with its edges at distance of x from centre
now (p*2x*A)/

= E*2x*l
for second question
electron....a=eE/me proton....a=eE/mp
let the pair was released at a distance of x cm from negative plate
so s=1/2 at2
using it t2 =x*(2mp)/eE=(2-x)*(2me)/eE
now solve it to get x!