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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:16:07 IST
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One or more than one correct: a negative point chage placed at the point A is:
A in stable eqm along x-axis B in unstable eqm along y axis C in stable eqm along y-axis D in unstable eqm along x-axis
plaese xplain in detail
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:18:37 IST
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D in unstable eqm along x-axis.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:30:01 IST
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ANSWER WILL BE UNSTABLE EQUILIBRIUM ALONG X-AXIS AND STABLE EQUILIBRIUM ALONG Y AXIS
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:34:16 IST
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hey friends, lakh salutes to xpalnation of it
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this word is so small that it is a foolishness to hate anyone.
so, we love all. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:36:32 IST
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tomorrow. i think i solved it. if it is +ve charge it will execute shm alog y axis. i shall check tomorrow.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:36:58 IST
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see acc. to definitions of the stable and unstable equilibriums, in this case if we move the middle charge along x-axis then the force of attr btw the middle charge and the charge towards which its moved will increase...........hence unstable equilibrium
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Jan 2008 01:38:46 IST
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similarly if we move the charge along y axis then the horizontal componenta are cancelled and the vert comps add up. therefore the forces tend to bring the charges back to the initial position and hence stable equilibrium..........
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