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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:04:16 IST
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COUD U PLEASE EXPLN WHY THEY R IN PARALLEL
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
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http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:15:49 IST
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it is parallel between across the middle resistor
across the two ends it is
--------///----///------------- |__///____| Use Geometrical symmetry or kirchoff's law to do these problems
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:21:33 IST
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DIDNT UNDERSTAND
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:25:39 IST
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I CAN SOLVE IT USING KIRCHOFFS LAW BUT IT IS 2 LENGTHY
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:32:37 IST
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Sorry for my earlier reply it is indeed a parallel connection See the image Rate me
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:35:54 IST
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HOW CAN U REPLACE THE DIAGRAMS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2008 10:43:38 IST
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I haven't replaced the diagrams just rearranged the geometry without changing any connections.
Check HCVERMA electric current problem 30 its the same problem you can move around the resistors physically without changing the arrangement
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 00:58:58 IST
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Hi! Notice that the wire connecting the leftmost plate of the leftmost capacitor also connects the rightmost plate of the middle one. See , they are in parallel. Now can go for the same logic with the third one and see yourself. Also make use of the fact that P.D. between the two capacitors is the same (Similarly for the third);
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 02:11:51 IST
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mark the two end terminals as A and B. Check the plates of each capacitor and you will find that if one plate is connected to A the other will be connected to B. It implies that all the capcitors share the same potential difference and hence they are parallel
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