please confirm he answer for this question

i am getting the answer as 4.43 X 10 to the power - 11

 

two square plates of side 1 m are kept 0.01 m apart like a parallel plate capacitor in air such that one of their edges is perpendicular to the oil surface in a tank filled with an insulating oil. the plates are connected to a battery of emf 500 V . the plates are then lowerd at the rate of 0.001 m per second. calculate the current drawn from the battery during the process

dielcetric constant of oil =11 and value of absilon not =  8.85 X 10 to the power (-12)

If V is voltage supplied K dilectric constant v velocity of capacitor and d seperation between plates than

i = V(K-1)epsilon_not*v/d

=500*10*8.85*10^-12*0.001/0.01 = 4.43*10^-11

You have got right answer