IIT JEE , AIEEE Forum - Physics , Electricity

golu_1234

Two small equal spheres carrying unlike and unequal charges are placed8 cm apart and attract each other with a force of 4 x 10^-5 N.After thay have been connected vfor a moment by a thin conducting wire,they repel each other with a force of 2 x 10^-5 N.Calculate their original charges.

krishna.gopal

Charge on sphere's be q1,q2.
Then kq1q2/(0.08)^2 = -4*10^-5N
After conection charge on each sphere is (q1+q2)/2 Let this be q.
Then kq^2/d^2 = 2*10^-5
So (q1+q2)^2/(q1q2)=-2
So (q1/q2)+(q2/q1)+2=-2
Let q1/q2=x
x+1/x=4
Solve to get x
This will give you q1/q2 and then put it in first equation to get q1 and then q2

chinmay_saxena01

it is given that charges r of opposite nature....so if one is q1 then other should be -q2 .......sir i want to know that after connecting them with a wire charge on each will be q1+q2/2 or q1-q2/2.

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