IIT JEE , AIEEE Forum - Physics , Electricity - Please solve this basic electricity qns rates assured

rakesh61

In the given circuit with steady current find potential drop across the capacitor

eragon007

try usin kirchoffs laws

saurabh_reincarnated

stedy current means ...........

t=infinity.......

so cap. acts as a conductor........

thn use superposition priciple or kirchoffs laws

k

Cheers!!!!!!

feynmann

ans V/2 .

Here capacitor branch is open at steady state .

madman

ya once the capacitor is fully charged there will not be any current in its branch
consider only the outer circuit
V = 2IR
I=V/2R
potential difference between across the branch = V + R * V/2R
= 3/2V
potential difference across capacitor = 3/2V - V = V/2

Ask & Discuss Questions with Community & Experts