IIT JEE , AIEEE Forum - Physics , Electricity

nikhil_iitian

given a hollow hemisphere. find the electric field and electric potential at the origin??

kindly imagine the figure u r self..its a hollow sphere with radius r .
pls do reply..!!!

coolyog

i acnt giv detailed soln

but dude

potential will be half of what it will be due to a full sphere(coz it is scalar nd can be added)

nd abt elecrtic field..it can be easily calculated by assuming rings...

Mr.IITIAN007

I agree with coolyog.

titun

For a hollow sphere, the potential at the surface = the potential at the centre

= q/4

₀ r

Now, the potential being a scalar quantity and by symmetry,

potential at the centre due to one hemisphere = 1/2 x the potential at the centre

due to the sphere = q/8

₀ r

thevyzz

coolyog's approach is correct

@titun, the centre should be considered such that it lies just outside the cavity

him26.89

electric field is

/4epsilon.

consider ring as an elementary part.

dE = K(dQ)x/(r^2+x^2)^3/2.

dQ=

(2

RCost)Rdt

x = Rsint

integrate it from 0 to pie/2.

remember, r = RCost

shubhayan_c

Simple yaar use gauss law u'll get the answer as
Sigma * 2 (pi) r^2 / 2 epsilon

i m considering the charge density on the hemisphere as sigma.

Tell if i m correct

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