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ashgirl (1434)

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a parallel plate capacitor has plates of area A separated by a distance d. a metal block of thickness h is inserted midway bw the plates. find the capacitance.
 
i got the answer but there is 1 more question along wid it.
 
DOES THE CAPACITANCE CHANGE IF THE BLOCK IS MOVED SO THAT IT TOUCHES ONE OF THE PLATES?????

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madman (239)

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it will because once it touches one of the plates it becomes a part of the capacitor.and the capacity of a capacitor depends on its dimensions.

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neeraj_agarwal_1990 (887)

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it won't change on changing the distance ......
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ashgirl (1434)

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welll!!!! which is the correct one???

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engg_pradeep2010 (2)

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when it touches then it will definitetly a part of capacitor.
capacitor will have one plate thick and one plate thin.thats it
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neeraj_agarwal_1990 (887)

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yeah...i didn't see....its a metal block....so it shud vary.....
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anpm_dev (111)

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Yes of course the distance between the plates is going to be less than by h but the area of the plates is going to be the same, the rest is going to be same
So capacitance will be (epsilon not*Area/(d-h))
Please correct me if i'm wrong.

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lokeshsardana (685)

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well try guys............

actually when metal block is midway between plates of capacitor
it will behave like 2 capacitors with distance between their plates as (d-h)/2 conected in series with each other.......so, nett capacitance is (epselnot)A/(d-h)


and also if metal block touches one of the plate........then a single capacitor will be formed.with distance between its plates as d-h
so, in this case capacitance is (epselnot)A/(d-h)............

so, capacitance is same in all cases even when block touches one of plates...........

tell me if I m wrong anywhere..............

and pls donot rate me 4 this..........

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anpm_dev (111)

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yes lokesh u might be correct

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aditya_arora04 (1077)

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u r correct, my friend lokesh !!

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