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Electricity

Blazing goIITian

Joined:	5 Dec 2007
Post:	704

24 Mar 2008 21:06:40 IST

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458

plz solve this !

None

problems from H . C. Varma

page no	qestion Number
142	14,15,21
164	4
165	4
166	15,20,21,22,
167	23
168	33,38,39,40,43,
169	47,48,
170	66,68

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Comments (9)

gokul subramanian

Blazing goIITian

Joined: 28 Jan 2008

Posts: 1451

24 Mar 2008 21:08:51 IST

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its gonna take a yr to answer all ur doubts...
i think it will also be useful if u make an online version of hcv..so tht every1 can try

BILLA

Blazing goIITian

Joined: 14 Mar 2008

Posts: 447

24 Mar 2008 22:31:58 IST

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Aaaah so many doubts ah i too dont have HCV plz supply an online version of HCV plz as gokul said!!!!

VARUN RAJ

Blazing goIITian

Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 22:42:53 IST

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see sum no 15
let the battery supply a charge Q1+Q2
Q1=4(v-vc)
Q2=8(vc)
Q2-=3(v-vd)
q1=6vd

4v-4vc=8vc
v=3vc
3v-3vd=6vd
v=3vd v=50 vc=vd=50/3
therefore the potentiol difference at points c and d are same so if a capacitor is connected no charge will flow through it
eq.

VARUN RAJ

Blazing goIITian

Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 22:46:13 IST

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sum no 47
q1=120
q2=72
q1=q2=48
in stable state the v across the capacitors is the same
q1/5=q2/6
q121.8,26.2

VARUN RAJ

Blazing goIITian

Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 22:52:15 IST

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pg 164 sum no 4
since the v across the last capacitor at both the points is the same no charge will flow through it.it can be excluded from calculations
the other 2 capacitors r in parallel therefore the eq. capacitance=2c

VARUN RAJ

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Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 22:57:27 IST

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pg 165 sum no 4
draw a gaussion surface between the plates of the capacitor
since the lenth lies in the conductor the electric flux and the electric field is 0 since no electric field can exist in a conductor
therfore the facing surfaces of the capacitor will have the same charge the outer surfaces will also have the same charge acoording to gauss law.
and the battery will always supply th same charge to both the plates . so the answers are a,c,d

VARUN RAJ

Blazing goIITian

Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 23:05:56 IST

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sum no 39 let the capaciance be c and v
cv^2=4
when the capacitors r joined in series the eq. capacitance becomes c/2
the potentiol difference across the ccapcitors will remain the same
cv^2=4
thereforec/2v^2=4*0.5=2

VARUN RAJ

Blazing goIITian

Joined: 16 Mar 2008

Posts: 1825

24 Mar 2008 23:06:33 IST

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at least rate me for my efforts

dont u know me

Blazing goIITian

Joined: 5 Dec 2007

Posts: 704

26 Mar 2008 00:12:40 IST

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hey varun i asked Q no.4 of exercise not from objective can u also answer me 21 Q of subjective [exercise] please i have grand test 2 morrow

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