IIT JEE , AIEEE Forum - Physics , Electricity

nasa_hs

A hemisphere of radius R is charged uniformly with surface density of charge sigma.What will be the potential at the centre?

sigmaR/2E₀

sigma/4E_o

sigma/2E₀

4sigmaR/3E₀

( E_o is permittivity )

robberno

V=KQ/R
=SIGMA4PIE R^2/4PIE E0 R
=SIGMAR/E0

a_JOSHI

i think it should be sigma/4E0

indrajeet_bariar

Using integration, i got the answer sigma/4E0

Terminator.HCV

using Gauss' law get
E.2.pi.R^2=(sigma*2.pi.R^2)/E0
or, E=sigma/E0

Now, E=-dV/dR
or, V=intergrtn(E.dR) lowr limit=R upper limit=0
or, V=sigma.R)/E0

indrajeet_bariar

@TERMINATOR.HCV
WILL U BE GENEROUS ENOUGH TO TELL US WHICH TYPE OF GAUSSIAN SURFACE U R USING IF U R USING GAUSS THEORUM.