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Electricity

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13 Jul 2009 10:39:39 IST

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Que on Flux...

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Que : 2 Point charges q and -q are placed 2l distance apart. Find the flux of the electric feid strength vector across a circle of radius R.

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BALGANESH

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Joined: 21 Dec 2007

Posts: 1025

13 Jul 2009 10:48:04 IST

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electric field at the cirlce due to Q = kQ/l^2

electric filed at teh circle due to -Q = kQ/l^2

both in same directionso they add up total electric filed = 2kQ/l^2

now flux acroos the circle = E.s

= 2kQ./l^2 * pie R^2

= 2kQ pie R^2 / l^2

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