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19 Mar 2008 21:38:26 IST

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QUES ON GUASS LAW.............

None

IF THE RADIUS OF THE GUASSIAN SURFACE ENCLOSING CHARGE IS HALVED, HOW DOES THE FLUX THROUGH THE GUASSIAN SURFACE CHANGE ..........

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Neeraj Agarwal

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19 Mar 2008 21:41:31 IST

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flux depends only on the charge.... its q/e (e is epsilon)

so it will remain the same...

Sai Ganesh Bandiatmakur

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19 Mar 2008 21:47:31 IST

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@ neeraj:
i dont think that it is necessary to remain the same, consider a solid sphere of rad r charged over total volume, and gaussian surface has a radius r/2?( it is not given as "point charge" rite??)

Neeraj Agarwal

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19 Mar 2008 21:50:20 IST

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but i think the charge mentioned should be a point charge....dats why is the question made!

the question cannot be answered any other way if its objective...

harsh _27

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19 Mar 2008 21:55:37 IST

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Priyesh......Your question is incomplete.
If it is a point charge then Neeraj is correct.
Otherwise it must be mentioned abt the distribution of charge.

edison

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20 Mar 2008 08:45:26 IST

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If radius of gaussian surface is halved and charge still remains within the gaussian surface, then FLUX THOUGH THE SURFACE REMAINS THE SAME

As, Flux = q/

₀

So it does not change as it is independent of area

But the parameter that changes here is FLUX DENSITY i.e. Flux/Area

So initally area is = A = 4

r²

then if radius is halved A' = 4

r²/4 =

r²

So A/A' = 4

Hence, flux density increases by a factor of 4

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