IIT JEE , AIEEE Forum - Physics , Electricity

budokai_tenkaichi

find roots of equation
(x+1)^1/2-(x-1)^1/2=(4x-1)^1/2

cutie_divs91

firstly,i dont think so that this is a question of electricity,whatever,here is ur solution-

squaring both sides-

x+1+x-1-2(whole root(x+1)whole root(x-1))=4x-1

=2x-2(whole root(x+1)whole root(x-1))=4x-1

=2(whole root(x+1)whole root(x-1))=1-2x

squaring both sides again

4(x+1)(x-1)=4x²+1-4x

=4(x²-1)=4x²+1-4x

=4x²-4=4x²+1-4x

=4x=5

x=5/4(ans)

cutie_divs91

hey....i substituted the value in the equation but the value is not satisfying it.......can anyone tell me where the problem is.....

nadeemoidu

There is no problem . whenever u square an equation , u should substitute and check in the end . if it does not satisfy the equation , then it is not a root. that's all . u should do that always when u square.

sandeepramesh

OMG! He posted this sum in the physics forums too?

see here

anandghegde

@budokai

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