IIT JEE , AIEEE Forum - Physics , Electricity

aquafina_1991

A truncated cone is made of materials X and Y as shown. The radii of the two vertical surfaces are a and b (b > a). The resistivity of X is p and Y is a superconductor. Calculate the resistance between the two vertical surfaces. Assume, b - a << l.

bhuwanaroracorroded

hey d answer should b zero

a more basic one is given one in HCV

hey if u consider that result given in hcv 4 a simple truncated cylinder

let R 4 a simple truncated cylinder cylinder is R then to get the net result of ur diagram

take seperately that superconductor 4 a timebeing then the bigger truncated cylinder will be have a hollow part inside it which can b considered as a

combination of two truncated cylinder one d bigger one without any hole and the other one that is d hole as truncated cylinder wid with -ve resistivity

now the net one can b calculated it to be parallel wid d complete one

now also take d truncated superconducter cylinder in parallel wid it

note here it is a superconductor therefore R=0 for d superconducter one hence net resistance of d combination zero

bhuwanaroracorroded

4 a simple truncated cylinder resistance=l/ab

rate if useful

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