IIT JEE , AIEEE Forum - Physics , Electricity

umang

HC Verma , pg-198 , Ch-electric current ,

Que-10 . (Figure shows a conductor ......................of the conductor )

him26.89

change in radius per unit length = (b - a)/l = k (suppose)

then radius at a distance xfrom base (radius b) = b - kx

now

dR =

dx/

r²

on int

R= (

/

)_{[ ]}

^{[ ]} {1/(b - kx)²} dx [limits are 0 to l]

after int put value of k.

hence, R=(

/

)(l/ab)

umang

Hey him26.89 ,

I am not able to understand clearly . Can u explain ?????

Thank you !

Jyoti123

Look R = rho l / A
So, R = rho l / pie a b ( since from the diagram it is clear that Area of cross section= pie a b)

Jyoti123

Oh no the diagram is not being attached. Give your id umang I will send a word document containing the diagram.

umang

Pls send me as soon as possible !!!

Thanks !!