IIT JEE , AIEEE Forum - Physics , Electricity

city_gal1234

1)find eff resistance bet A&B

2)voltmeter v1 and v2 are in series.(d.c)

v1=80v and per volt resistance-=200ohms

v2 has a total resistance of 32kohms

wat is line voltage?

3)a cell dissipates the same power across each of resistances r and R.wat is internal resistance of the cell?

city_gal1234

plzzzzz somebody help.

Prakriteesh

In the left triangle the (3+7)=10 ohm is in parallel with the 10 ohm. Thus for that part Req = 5 ohm. Now (5+10) ohm =15 ohm is in parallel with 30 ohm. Thus Total Req = 10 ohm.

Since per volt resistance R/V= 200, so V/R = i = 1/200. So, total voltage drop = i.(total resistance) = 1/200 . (80X200 +32000) = 80+160 = 240 volts.

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