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Electricity

Cool goIITian

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15 Apr 2009 20:32:22 IST

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the length of each side of a cubical closed surface is L.......

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the length of each side of a cubical closed surface is L.if charge Qis situated on one of the vertices of the cube then find the flux passin through one of the face of the cube.

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NugoRama

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15 Apr 2009 20:34:16 IST

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q/48e see..

.charge inside ::q/8

..so total flux passing out ::q/8e

so from each face (six faces in all...duh..) ..q/48e

vasantha

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15 Apr 2009 20:34:32 IST

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yah

Sachin.K

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15 Apr 2009 20:40:34 IST

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WRONG ANSWER

vasantha

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15 Apr 2009 20:41:33 IST

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y is it wrong so

NugoRama

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15 Apr 2009 20:42:18 IST

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then, thankyou..anything else u want sir ..i have,besides wrong answers,wrong questions,wrong wrongs etc.

Stepping Ahead Of Succez

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15 Apr 2009 20:42:23 IST

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is there any reason that u r correct vasantha????

negative marking

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15 Apr 2009 20:44:23 IST

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yup....answer given by nugorama is wriong..bcz charge is not symmetricallly placed here.....i don kow the rioght one...n surely wud like to know!

Sujit

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17 Apr 2009 07:48:23 IST

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answer is Q/24 place 7 similar cubes in such a way that the vertex of the cube containing the charge is at the center applying gauss's law we get the flux thru each surface as Q/6but ny placing those 7 cubes we have increased the surface area of each cube which is actually 4* initial surface areathere fore flux through the initial cube is (q/6)/4=Q/24

BALGANESH

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17 Apr 2009 10:53:28 IST

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since it is on one of the vertex it is shared between 8 cubes....so charge in the cube = Q/8eo ..........now the flux thru each face thoguh it has 6 faces only 3 faces will be considered so q/3*8 e0 = q/24eo

NugoRama

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17 Apr 2009 10:54:45 IST

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thnx 4 correcting ...rohit. n sujit.

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