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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 10:40:18 IST
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three identical charges are placed at the corners of an equilateral triangle.if the force between any two charges is F ,then net force on each charge will be?(a)root2.F,(b)2F,(c)root3.F,(d)3F
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 10:45:19 IST
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c)root3F
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 10:46:59 IST
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But how,please explain
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 10:52:36 IST
Accepted Answer [?]
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The net force on one of the charges is F & F with an angle 60 degrees between them.so,net force=2FCos30= 3F
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 11:04:26 IST
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underroot 3f is answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 11:14:46 IST
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please explain in details.I will surely rate ur answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 11:14:48 IST
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answer is root3f.......ziiauddin is correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:14:30 IST
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well the net force F' on any charge is = (root 3) F F'= (F2 + F2 + 2F2 cos60o)1/2 after solving u get the required answer plz rate if i was helpful
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