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Electricity

Cool goIITian

Joined:	8 Apr 2009
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26 Jun 2009 21:40:22 IST

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Two heaters designed for the same voltage V have different power ratings. When connected individuall

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Two heaters designed for the same voltage V have different power ratings. When connected individually across a source of voltage V ,they produced H amount of heat each in time t1, and t2, respectively .When used toghter across the same source , they produce H amount of heat in time t (a) if they r in series ,t = t1+t2(b) if they r in series ,t = 2(t1 + t2)(c) if they r in parallel ,t = (t1 x t2)/( t1 + t2)(d) if they r in parallel ,t = (t1 x t2)/2( t1 + t2)

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Kshitiz Kumar

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Joined: 29 Apr 2009

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26 Jun 2009 22:46:51 IST

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hi Aman, the ans to your question is a) and c),

if i am correct nudge me, i 'll give you the solution

Kshitiz Kumar

Cool goIITian

Joined: 29 Apr 2009

Posts: 39

27 Jun 2009 14:23:25 IST

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let and be the resistances....we know that power= and power x time=heat energy

therefore we can write and and so we can write R1 and R2 as:

and hence when the are in series :

and when they are in parallel now apply and to get values

of " t "for series and parallel respectively.

Don' t forget to rate me pls...

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