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12 Mar 2010 20:11:53 IST
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what is the force exerted by 1 plate of capacitor on the other ?
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what is the force exerted by 1 plate of capacitor on the other ?


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New kid on the Block

Joined: 12 Mar 2010
Posts: 3
12 Mar 2010 22:38:04 IST
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the force between 2 plate is of magnitude........F=Q^2/2Aε and is attractive in nature.......
siDDhESwaR MuKhErjEE's Avatar

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Joined: 15 Nov 2009
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20 Mar 2010 19:46:49 IST
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We consider a parallel plate capacitor.Now the electric field due to a plane sheet of charge is Q/2Ae.This can be calculated using gauss law.

Thus the field existing between two plates of a capacitor is Q/2Ae.Here Q is the magnitude of charge existing on each plate. But the charges on the two plates are opposite in sign. Thus if the charge on the plate setting up the charge is Q, then the charge on the other plate is -Q.

As we know, F=Q*E

Thus force acting on the other plate due to the first plate is(-Q)*Q/2Ae.

As we know force between charges of opposite signs is attractive................So here is the answer to your doubt

edison's Avatar

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Joined: 19 Oct 2006
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31 Jan 2011 21:19:54 IST
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 If charge on teh plate = Q

then F = QE

here E = charge density / Permitivity in free space




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