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Electricity

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 Joined: 5 Nov 2011 Post: 5
23 May 2012 16:21:33 IST
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Find X in this Question.
Engineering Entrance , Medical Entrance , NEET , JEE Main , AIIMS , JEE Main & Advanced , Physics , Electricity

A non conducting rod of lenght 'l ' is pivoted at its centre with a weight 'w ' at a distance X from the left end of the rod. At the ends of the rod are attached small conducting spheres with charge q and 2q which lie at distance 'r ' from the fixed charges Q . Find X=?(Please answer in detail)

Blazing goIITian

Joined: 22 May 2009
Posts: 2467
8 Jul 2012 18:49:42 IST
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Just balance the torque for all of the forces about the pivot.

Two are the coloump force of repulsion.

The balancing of torque about the pivot will give u the answer in single step.

( k*Q*q/r^2)*l/2+W(x-l/2)=k*2*q*Q/R^2*l/2

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