Home » Ask & Discuss » Physics
« Back to Discussion

Electricity

New kid on the Block

Joined:	5 Nov 2011
Post:	5

23 May 2012 16:21:33 IST

0 People liked this

242

Find X in this Question.

Engineering Entrance , Medical Entrance , NEET , JEE Main , AIIMS , JEE Main & Advanced , Physics , Electricity

A non conducting rod of lenght 'l ' is pivoted at its centre with a weight 'w ' at a distance X from the left end of the rod. At the ends of the rod are attached small conducting spheres with charge q and 2q which lie at distance 'r ' from the fixed charges Q . Find X=?(Please answer in detail)

Comments (1)

Juhi Sharma

Blazing goIITian

Joined: 22 May 2009

Posts: 2467

8 Jul 2012 18:49:42 IST

Like 0 people liked this

Just balance the torque for all of the forces about the pivot.

Two are the coloump force of repulsion.

The balancing of torque about the pivot will give u the answer in single step.

( k*Q*q/r^2)*l/2+W(x-l/2)=k*2*q*Q/R^2*l/2

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team