When a capacitor is charged the potential energy stored in it is 1/2 CV^2. Isn't the work done to charge a capacitor CV^2 as half the work done is dissipated as heat?(efficiciency of a capacitor is 50% isn't).
On any plate of the capacitor , the force is Q*r / 2 E0 instead of Q*r / E0 .. where r is surface charge density
so the work done is 1/2 CV^2
and the statement is wrong that efficiency of a capacitor is 50%
NO dude..go and check the lectures of MIT , then come and tell ..!! the concept is a little HATKE and the reference books have many mistakes ..!!
kbhi time mile to samjha doonga ..!!
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