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Games, Puzzles and Quizzes

Blazing goIITian

Joined:	2 Mar 2007
Post:	754

13 Jan 2008 13:19:39 IST

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1125

solve this....amazing puzzle

None

there are 12 coins of identical shape.
out of the 12 coins , 1 coin is fake
the weight of the fake coin is either less or more than the weight of the other lot
there is a wweight balance.

you r to weigh 3 times,and find out which coin is the fake 1,,and also find out wheather the fake coin is heavier or lighter than the real coins
!!!!

answer it....in 2 day's time

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Comments (5)

karthik

Blazing goIITian

Joined: 25 Feb 2007

Posts: 1010

13 Jan 2008 14:16:08 IST

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I could find only wen ,the fake coin is either heavier r lighter[i.e. only if given

If the fake is heavier,then,

divide 12 coins into 6 coins each and find the one which is heavier

from the hevier 6 divide into 3each and find the heavier

from the heavier 3, select 1 coin and 1 coin and weigh them..and find the heavier one...if both r equal the left out coin is the heavier one

Raghudevan Shankar

Blazing goIITian

Joined: 19 Aug 2007

Posts: 352

14 Jan 2008 07:38:36 IST

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first divide the coins into groups of four each

then use the balance once, if they weigh the same then the defective coin is in the third batch

now take two coins from the defective batch and weigh, if one of those two coins are def, then it'll weigh less or more. take the less weighing coin and weigh with the other coins, if it still dosent balance then that coin is the def coin

karthik

Blazing goIITian

Joined: 25 Feb 2007

Posts: 1010

14 Jan 2008 09:17:14 IST

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@raghu,

u weigh the 4 coins.........and wat will u do if they r not equal?

which one will u select? heavier 1 r lighter 1?this is what is troubling me!as the fake coin can either be heavier r lighter.......

Himanshu

Forum Expert

Joined: 19 Feb 2007

Posts: 3834

14 Jan 2008 12:34:04 IST

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A very simple puzzle actually.

Make 3 groups with 4 balls each. Lets say A , B, C with individual balls named A1, A2 etc..

Now weigh A & B. If both r equal the ans is simple and solved.

If A > B then either one ball of A is heavier or one of B is lighter with all balls in C proper.

Now make two groups put C1- C4 & B4 in one group & B1- B3 , A1, A2 in other group. Name these groups say X & Y.

If X < Y either B4 is lighter or A1 or A2 is heavier which can be made in one chance.
If X > Y then one of B1- B3 is lighter which can be made in one chance.
If X = Y then one of A3, A4 has a defect which can be made in one chance.

Thus he puzzle is solved.

suhail

Cool goIITian

Joined: 23 Mar 2008

Posts: 69

7 Jun 2008 21:08:09 IST

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divide into 3 grps of 4. weigh ne two. if any1 is lower its heavier, or else its da third. take tht grp n divide it into two of 2 coins. weigh them 2 c which grp has da heavier coin.then weigh those 2 opposite each other.

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