IIT JEE , AIEEE Forum - Physics , General

anshulpatel

tell me the
graph of ...

y = sin(x) / sin(x)

it's challenge...

plzzz see m article on one topic of topic of IITJEE..

http://www.goiit.com/posts/list/community-shelf-formulae-28364.htm

spideyunlimited

this is just the graph of y = 1 except at points where x is such that sin x = 0.
x = n.pi at all other points graph is defined and is the graph of y = 1 .. at x = n pi however graph will break

VIV

singhshivendra

noooooooooo . the value of x changes . suppose x is 45 so at rhs we will get sin1 that is 90 degree.

prashant_prakhar

hey viv u r absolutely correct

anshulpatel

PLZZZZZ HELP

spideyunlimited

dude my answer is correct.. graph is just as viv has drawn except that the points will not be included where sin x becomes 0 as sin x is in denominator.
Here everyone makes a mistake of just cancelling sin x / xin x and making it one.. we can only cancel sin x in numerator and denominator if it is not equal to 0.. remember?basic rule of math.
hence graph breaks at 0, pi, 2pi, 3pi, 4pi etc.

karthik2007

Yes, spidey is right. The graph is not defined when x takes values that are integral multiples of pi or when it is zero

mujtaba4iit

The guys are correct. The graph will be parallel to the x-axis at a distance of 1 unit above it.

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