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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Nov 2007 23:02:06 IST
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A body of mass 'm1' is moving with velocity ' v ' in specific direction. This body was weighed before movement and found that its mass was 'm1' initially and during the tenure of motion the mass of the body was found to be 'm2'. What is the relation of mass with its movement ? If there is any relation what is it and why was the mass affected? C'mon Guys please help me out with this ques... A Good Explination will get 3 salutes for sure
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According to Theory of relativity , when a body is in motion with velocity V , then its mass is given by m = m0/(1 - v2/c2)1/2.where m0 = rest mass (or mass of body in rest).
Therefore before movement, v=0. Hence mass = m0 = m1
During movement mass increases according to the given formula Hence m2>m1..
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23 Nov 2007 23:12:10 IST
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but then can u explain me why does this takes place why do the mass of the body in general gets affected due to motion of the body
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23 Nov 2007 23:40:47 IST
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This is a ques based on einstein's super famous theory of relativity
u shud understand that no body can travel with speed grtr than velo of light bcoz according to given eqn by rooney, its mass wud becomes infinite at v = c
so mass increases when the body is in motion
now if u ask why then i dont think i have the answer, indeed theory of relativity is taught in BTech, ques based on this wont come in any entrance test.......so u must not worry....cheerz!!
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23 Nov 2007 23:52:11 IST
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Momentum is conserved in any frame.
So, mdy/dt = m0dy/d (Assuming that relative vel of frame is only along x-axis. So conserving momentum along y-axis)
LHS is as observed by observer in his frame of reference of rest S.
RHS is as observed by another observer in frame of reference S' of object which is moving with relative vel. v with respect to the S.
m=m0d/dt
Now d is the time period measured by observer in frame of reference S' of object.
dt " " " " " " " " " " " S.
There is something called time dilation. Means that when you measure the time period of event taking place in another frame of reference moving with vel. v , the time you measure is more than the actualy time period by a factor of (1 - v2/c2)1/2.Hence,
d/dt = 1/(1 - v2/c2)1/2.
Put this in earlier equation ,
m = m0/(1 - v2/c2)1/2.
Hope it helps.
-Rohil
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