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dbc (2)

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tell me something about graphical representation of motion(acceleration time graph and velocity time graph)
 
           by v.agam
                     9 class.


V.AGAM
9 th CLASS
    
dbc (2)

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answer??????????????????????????


V.AGAM
9 th CLASS
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titun (1529)

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If the displacement of a particle, x be a function of time t,
 
i.e. x = f (t), then, the velocity of the paricle, v = dx/dt = f ' (t)
 
& acceleration of the particle, a = dv/dt = d2x/dt2 = f '' (t)
 
In the graphical representation of motion of a particle, the following points must be remembered :
 
1. In the displacement-time graph, the slope of the graph at any point gives the velocity of the particle at that instant of time.
2. In the velocity-time graph, the slope of the graph at any point gives the acceleration of the particle at that intant of time. 
3. In the velocity-time graph, the area under the curve gives the total displacement of the particle in the given time interval, since
[b][a] v dt = x ,where, x is the displacement of the particle in the time interval
(a-b)
 
Now some common questions which you will come across.
 
1. When x-t graph is a straight line ( x-t graph can never be perpendicular to the time axis, as it means that the particle is at diff. positions at the same instant of time which is absurd ), then v = dx/dt is constant i.e v-t graph is a st. line parallel to the time axis, and a = dv/dt = 0
2. When x-t graph is a parabola of the form x=kt2, then v = 2kt i.e v-t graph is a straight line , not parallel to time axis,  & a = 2k, i.e a-t graph is a st. line parallel to the time axis
3. When the v-t graph is a parabola of the form v = mt2, then a=2mt, & a-t graph is a straight line passing through the origin.
 
Since you are in class 9, I believe, you don't know 'slope'.
'Slope' at a point means the tan ( of the angle that the tangent to the curve at that point makes with the positive X-axis )
I think you may not know about integrals much, in calculating area, mainly simple areas, formulas should be used. Like in case of a
square : area = l2 sq. units , l = length of each side
rectangle : area = lb sq. units l = length b = breadth
triangle : area = 1/2 h b sq. units h = altitude b = base
parallelogram : area = b h sq. units  b = base , h = height
 
Well, the above are the basics of graphical representation of motion of a particle. I've shown how to go about this type of problems, so hope I am of some help to you.
 
Cheers !!!

You never know what is enough till you know what is more than enough.

Titun
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neeraj_agarwal_1990 (887)

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well...can anybody from class 9 understand these concepts!!

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avinash.sharma (1189)

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The Meaning of Shape for a p-t Graph

The study of 1-dimensional kinematics has been concerned with the multiple means by which the motion of objects can be represented. Such means include the use of words, the use of diagrams, the use of numbers, the use of equations, and the use of graphs. In this article I will focuse on the use of position vs. time graphs to describe motion. The specific features of the motion of objects are demonstrated by the shape and the slope of the lines on a position vs. time graph.
 
To begin, consider a car moving with a constant, rightward (+) velocity of 10 m/s. (Figure0)
If the position-time data for such a car were graphed, the resulting graph would look like the graph at the right. Note that a motion with constant, positive velocity results in a line of constant and positive slope when plotted as a position-time graph (Figure1).
Now consider a car moving with a changing, rightward (+) velocity ? that is, a car that is moving rightward and speeding up or accelerating (Figure2).
If the position-time data for such a car were graphed, the resulting graph would look like the graph at the right. Note that a motion with changing, positive velocity results in a line of changing and positive slope when plotted as a position-time graph (Figure3).
The position vs. time graphs for the two types of motion ? constant velocity and changing velocity (acceleration) ? are depicted in the Figure4

 

The Principle of Slope for a p?t Graph


The shapes of the position vs. time graphs for these two basic types of motion ? constant velocity motion and changing velocity motion (i.e.accelerated motion) ? reveal an important principle.
The principle is that the slope of the line on a position-time graph reveals useful information about the velocity of the object. It's often said, "As the slope goes, so goes the velocity."
Whatever characteristics the velocity has, the slope will exhibit the same (and vice versa). If the velocity is constant, then the slope is constant (i.e., a straight line). If the velocity is changing, then the slope is changing (i.e., a curved line). If the velocity is positive, then the slope is positive (i.e., moving upwards and to the right). This principle can be extended to any motion conceivable.
 
To explain the topic I need more pics but limit is only 5 pics at a time. So Please ask about acceleration graph as a new question.





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edison (4929)

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Thats perfect answer.

The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp.
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devesh_l2k007 (107)

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and 1 more thing take care that the parabola oens up when acc and down wen dec

devesh

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