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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:05:46 IST
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OUT OF 8 COINS 1 IS SLIGHTLY HEAVIER THAN OTHER HOW TO DISTINGUISH BY ANALYZING GIFT FOR SELECTED ANSWERS REGARDING BITS PREPARATIONS
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:12:42 IST
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two groups of 4.. whichever is heavier contains the coin. Now two groups of 2 Then weigh separately
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:16:49 IST
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BY ANALYZING TAKING 4 COINS IN 1 HAND AND 4 IN OTHER CAN YU ANALYZA WHICH ONE IS HEAVIER ANY OTHER GOOD SOLUTION PLZ
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:20:47 IST
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If you don't wanna weigh, i can think of one more method.. Take a glass of water. One which sinks fastest is the heavier one
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 May 2008 11:00:08 IST
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from the computations point -
a. 3 and 3, this will tell which 3 or 2 (remaining) have it b. if grp of 3 has then take 1, 1, Or if a says grp of 2 then also take 1,1
so this is better as you can save no of tries.. min tries needed 2, max 3
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 May 2008 22:56:24 IST
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Take a transparent trough full of water and a cardboard on which u can place the 8 coins in succession. Now place the cardboard on the rim of the trough and tilt it so that all the coins enter the water at the same time. Now, observe the coins. The coin which reaches the bottom first is the heavier one. This method can do ur work in first attempt.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 00:43:49 IST
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easy
ROLL THEM DOWN AN ENCLINED PLANE
HEAVIER ONE WILL REACH FIRST!!
CONSIDERING COIN AS A DISC I=1/2MR(SQUARE)
AND would be same for all since mass will cancel
but in mg' the greater mass coin wins
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 May 2008 12:03:03 IST
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heyyy take 8 coins 7 will be in uniform weight and 1 will b heavier let uniform weight of coin be 1 gm nd heavier be x 1st weigh 1 coin and den 2 coin nd den 3 coins nd so on wen der is change in weight den it wil b d heavier coin
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