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General Physics

Blazing goIITian

 Joined: 10 Oct 2011 Post: 434
6 Jun 2012 22:50:53 IST
3 People liked this
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a ball is projected from ground with a speed of 20 m/s at an angle of 45 degrees with the
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a ball is projected from ground with a speed of 20 m/s at an angle of 45 degrees with the horizontal. There is a wall of 25 m height at a distance of 10 m from the projection point. The ball will hit the wall at a height of ?

New kid on the Block

Joined: 6 Jun 2012
Posts: 1
6 Jun 2012 23:01:55 IST
1 people liked this

7.5m

R=40m

y=x - x2/R

x=10m

Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
6 Jun 2012 23:32:24 IST
1 people liked this

use equation of trajectory put the given and find the unknown

Forum Expert
Joined: 29 Dec 2006
Posts: 5535
7 Jun 2012 09:19:17 IST
1 people liked this

Eq of trajectory is given by y = x*tan(@) -g*x2/2/(ucos(@))2

Put x = 10, u = 20, @ = 45 and g =10 we get y = 7.5 meter.

Blazing goIITian

Joined: 10 Oct 2011
Posts: 434
7 Jun 2012 12:35:15 IST
0 people liked this

thnk u

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