a ball is projected from ground with a speed of 20 m/s at an angle of 45 degrees with the horizontal. There is a wall of 25 m height at a distance of 10 m from the projection point. The ball will hit the wall at a height of ?
y=x - x2/R
Eq of trajectory is given by y = x*tan(@) -g*x2/2/(ucos(@))2
Put x = 10, u = 20, @ = 45 and g =10 we get y = 7.5 meter.
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