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Blazing goIITian

Joined:	10 Oct 2011
Post:	434

6 Jun 2012 22:50:53 IST

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a ball is projected from ground with a speed of 20 m/s at an angle of 45 degrees with the

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a ball is projected from ground with a speed of 20 m/s at an angle of 45 degrees with the horizontal. There is a wall of 25 m height at a distance of 10 m from the projection point. The ball will hit the wall at a height of ?

Comments (4)

Praveen

New kid on the Block

Joined: 6 Jun 2012

Posts: 1

6 Jun 2012 23:01:55 IST

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7.5m

R=40m

y=x - x²/R

x=10m

Tarun Garg

Blazing goIITian

Joined: 21 Mar 2012

Posts: 1457

6 Jun 2012 23:32:24 IST

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use equation of trajectory put the given and find the unknown

Krishna Gopal Singh

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Joined: 29 Dec 2006

Posts: 5535

7 Jun 2012 09:19:17 IST

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Eq of trajectory is given by y = x*tan(@) -g*x²/2/(ucos(@))²

Put x = 10, u = 20, @ = 45 and g =10 we get y = 7.5 meter.

PALASH

Blazing goIITian

Joined: 10 Oct 2011

Posts: 434

7 Jun 2012 12:35:15 IST

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thnk u

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