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General Physics

Blazing goIITian

 Joined: 10 Oct 2011 Post: 430
6 Jul 2012 22:41:42 IST
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a particle of mass m moving with a velocity v strikes a horizontal surface at angle theta
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a particle of mass m moving with a velocity v strikes a horizontal surface at angle theta with the vertical and rebounds with the same magnitude and at the same angle with the vertical. the magnitude of change in momentum is

Blazing goIITian

Joined: 26 May 2010
Posts: 1362
6 Jul 2012 22:51:14 IST
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2*m*v *cos(theta)(magnitude) (direction j cap) ....decompose the velocity vector and write the momentum in vector form...and do it similiarly for after rebounding....for change --final - initial ((Assume the standard coordinate axis with i cap and j cap))

Blazing goIITian

Joined: 26 May 2010
Posts: 1362
6 Jul 2012 22:51:40 IST
0 people liked this

its correct naa?

Blazing goIITian

Joined: 10 Oct 2011
Posts: 430
7 Jul 2012 06:41:59 IST
0 people liked this

ya it's correct...thnx

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