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Blazing goIITian

Joined:	10 Oct 2011
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6 Jul 2012 22:41:42 IST

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a particle of mass m moving with a velocity v strikes a horizontal surface at angle theta

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a particle of mass m moving with a velocity v strikes a horizontal surface at angle theta with the vertical and rebounds with the same magnitude and at the same angle with the vertical. the magnitude of change in momentum is

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rajat sharma

Blazing goIITian

Joined: 26 May 2010

Posts: 1362

6 Jul 2012 22:51:14 IST

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2*m*v *cos(theta)(magnitude) (direction j cap) ....decompose the velocity vector and write the momentum in vector form...and do it similiarly for after rebounding....for change --final - initial ((Assume the standard coordinate axis with i cap and j cap))

rajat sharma

Blazing goIITian

Joined: 26 May 2010

Posts: 1362

6 Jul 2012 22:51:40 IST

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its correct naa?

PALASH

Blazing goIITian

Joined: 10 Oct 2011

Posts: 430

7 Jul 2012 06:41:59 IST

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ya it's correct...thnx

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