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Comments (3)
the answer is b
upward force f(j)(vector)+P(1)=P*(-4(j)-0))
downward force f(i)(vector)+P(2)=P*(0-2(i))
where P=4p
P(1)=pressure*area of below section of the pipe
P(2)=pressure*area of above section of the pipe
P*(-4-0)=pressure*change in velocity which is dimensionally force inthe same way equate horizontal forces
here it is (-4-0)&(0-2) because using continuity equation you can find the valocity of the vertical segment that is 4m\sec
later along vertical directionchangein velocity is -4-0 similarly for horizontal direction
and on solving you will get f(i)=-16p & f(j)=20p
hence resultant force= 
this your b option
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