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General Physics

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 Joined: 4 Apr 2012 Post: 7
4 Apr 2012 11:58:33 IST
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If sec A + tan A = 5. Find cosecA + cot A.
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If sec A + tan A = 5. Find cosecA + cot A.

Blazing goIITian

Joined: 2 Mar 2012
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4 Apr 2012 13:05:19 IST
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New kid on the Block

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4 Apr 2012 14:10:09 IST
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1.5secA + tanA = 5then secA - tanA = .2hence 2tanA = 4.8tanA = 2.4secA = 2.6therefore cosecA +cotA = 1.5

New kid on the Block

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4 Apr 2012 15:08:26 IST
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can u explain me more accurately.please

Blazing goIITian

Joined: 21 Mar 2012
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4 Apr 2012 15:33:25 IST
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Blazing goIITian

Joined: 21 Mar 2012
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4 Apr 2012 15:37:07 IST
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uu have tanA+secA=5 this cn b wriiten as secA=5-tanA

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squaring both sides and replace sec2A=1+tan2A

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u get tanA=12/5

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u havwe tanA=12/5

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u can construc6t atriangle with perpendicular =12 and base=5

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u can find cosecA and cotA from this triangle

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and u get the answer is 1.5

New kid on the Block

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4 Apr 2012 15:44:28 IST
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If sec A + tan A = 5. Find cosecA + cot A.

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Joined: 23 Jan 2007
Posts: 7958
4 Apr 2012 16:10:44 IST
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sec2A - tan2A = 1  =>  (secA - tanA)(secA + tanA) = 1

secA - tanA = 1/(secA + tanA) = 1/5

Given secA + tanA = 5

Adding above two we get secA = 13/5

This produces a right angled triangle with base : b=5, perpendicular : p=12, hypotenuse : h=13

cosecA + cotA = h/p + b/p = 13/12 + 5/12 = 18/12 = 3/2

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