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9 Mar 2010 23:46:40 IST

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MI of a ring is mr^2. If we treat rings as elements of a disc as well as of a hemisphere,then MI

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MI of a ring is mr^2.If we treat rings as elements of a disc as well as of a hemisphere,then MI of a disc and of hemisphere should be same (becoz mass as well as perp. distance of every corresponding ring in both from the axis will be same (as someone has opened the disc to expand it into a hemisphere), but actually not. What is wrong in the concept?(here axis is the axis passing through centre and perp. to plane in both cases)

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