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27 Apr 2012 22:32:20 IST

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physics question

Engineering Entrance , Medical Entrance , NEET , JEE Main , AIIMS , JEE Main & Advanced , Physics

Sir my sister have a doubt in physics .A body of mass 5 kg is raised vertically to a height of 10 m by a force 170N. The velocity of the body at this height will be.

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Krishna Gopal Singh

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28 Apr 2012 03:51:10 IST

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work done = inc in kinetc energy + inc in potential energy. So KE = 170*10 - 5*10*10 = 1200J. So velocity = sqrt(2*1200/5)

sania

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28 Apr 2012 14:08:17 IST

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I am not getting the answer the as given in book .The answer is velocity 22m/s

KKKKKKKKKKKKKKKK

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1 May 2012 00:17:55 IST

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ITS 26.25mps

Avinash Bhat

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5 May 2012 13:29:03 IST

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Upward force applied: 170 N

Weight (acting downwards) = 9.8*5 N

Net acceleration (upwards) = (170 - 9.8*5) / 5 m/s²

= 24.2 m/s²

Assuming zero initial velocity, v(final) = sqrt(2*a*S) = sqrt(2*24.2*10) = 22 m/s.

@KKKKKKKKKKKKKKKK (I think u missed the subtracting the weight part)

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