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According to Newton's law of gravitation, the force of attraction (F) between the Earth and the object is F = ma (a = g) From equation (3) it is very clear that acceleration due to gravity does not depend on the mass m of the object. It only depends on the mass of the Earth (Me) and the distance from the centre of the Earth to the object. Gravitational Constant (G) = 6.6734 x 10-11 Nm2/kg2 Mass of the Earth (Me) = 6 x 1024 kg Radius of the Earth (Re) = 6.4 x 106 m The value of acceleration due to gravity on Earth is 9.8 m/s2. This means that when a body falls freely towards the Earth its velocity increases at the rate of 9.8 m/s during its motion. Similarly when an object is projected vertically upwards its velocity decreases at the rate of 9.8 m/s and eventually the velocity becomes zero. The height at which the velocity of an object moving against gravity becomes zero is described as the maximum height attained by the object. When the velocity becomes zero the object starts falling down, with an acceleration as if released from that height. Note :
Consider an object of mass m lying on or near the surface of the Earth. Let Me be the mass of the Earth and Re be its radius i.e., Re is the distance between the object and the centre of the Earth.
A Body of Mass m Lying on the Surface of the Earth




Numerical Value of Acceleration due to Gravity on Earth
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acceler ation due to gravity..in general...u r asking as in what ..be specific